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DC Cable Size Calculator: How to Size Wires

Updated · Standard formula, shown below

The calculator for this page is switched off while it is checked. The formula is below, and the worked example in the article shows how to use it by hand.

DC Cable Size Calculator: How to Size Wires

This DC cable size calculator determines the minimum cross-sectional area (in mm² or AWG) of a copper or aluminum wire needed for a given DC circuit, based on the current, voltage, cable length, and maximum allowable voltage drop. You enter the system voltage, one-way cable length, load current, and acceptable voltage drop percentage, and the calculator returns the required wire size in both square millimeters and AWG. It also shows the actual voltage drop and the resulting voltage at the load.

Formula

The calculator uses the standard DC voltage-drop formula:

A = (2 × L × I) / (σ × Vdrop)

Where:

  • A = cross-sectional area of the conductor (mm²)
  • L = one-way cable length (meters)
  • I = load current (amperes)
  • σ = conductivity of the conductor material (m/Ω·mm²): 56 for copper, 35 for aluminum
  • Vdrop = allowable voltage drop (volts), calculated as (system voltage × max drop %) / 100

The factor 2 accounts for the current traveling through both the positive and negative wires. The result is the minimum cross-sectional area; you should always choose a standard wire gauge that is equal to or larger than this value.

Worked Example

Using the default values from the calculator: 12 V system, 10 A load, 5 m one-way cable length, 3% max voltage drop, copper conductor.

  1. Calculate the allowable voltage drop: Vdrop = 12 × 0.03 = 0.36 V
  2. Plug into the formula: A = (2 × 5 × 10) / (56 × 0.36)
  3. Numerator: 2 × 5 × 10 = 100
  4. Denominator: 56 × 0.36 = 20.16
  5. A = 100 / 20.16 = 4.96 mm²
  6. The calculator rounds to 4.96 mm², and the nearest AWG is 10 (which has 5.26 mm²).

So for this circuit, you need at least a 4.96 mm² copper wire, meaning a 10 AWG or larger.

Why Voltage Drop Matters

Every wire has resistance, and that resistance causes a voltage drop when current flows. In DC circuits, this drop is especially noticeable because voltages are often low (12 V, 24 V, 48 V). A 3% drop on a 12 V system is only 0.36 V, but that can be enough to make lights dim, motors run slowly, or sensitive electronics malfunction.

Voltage drop also generates heat. The power lost in the wire is P = I² × R. If the wire is too thin, it can overheat, melt insulation, or even start a fire. This is why sizing is not just about performance—it’s a safety issue. The National Electrical Code (NEC) recommends a maximum 3% voltage drop for branch circuits, and 5% for the entire circuit including feeders.

How to Use the Calculator

Follow these steps to get the correct wire size for your DC circuit:

  • System voltage (V): The nominal voltage of your battery or power supply (e.g., 12 V, 24 V, 48 V).
  • Load current (A): The maximum current the load will draw. If in doubt, use the fuse rating or the device’s rated current.
  • One-way cable length (m): The distance from the power source to the load. Do not double it; the calculator already accounts for the return path.
  • Max voltage drop (%): How much voltage loss you can tolerate. 3% is standard for most loads; use 1–2% for sensitive electronics or long runs.
  • Conductor material: Copper is more conductive and common; aluminum is lighter and cheaper but needs a larger area for the same drop.

The result is the minimum cross-sectional area. Always round up to the next standard wire size. For example, if the calculator says 4.96 mm², you need at least 10 AWG (5.26 mm²), not 12 AWG (3.31 mm²).

Common Mistakes and Misconceptions

One of the most frequent errors is confusing one-way length with total loop length. The formula uses the one-way distance because the factor of 2 already accounts for the return path. If you enter the total length, you’ll get a wire twice as thick as needed—wasteful and expensive.

Another mistake is using the wrong conductivity value. The calculator uses 56 for copper and 35 for aluminum, which are standard values at 20°C. If you use a different source, you might see 58 or 34.7; the difference is negligible for sizing.

Some people also forget that the voltage drop percentage is relative to the system voltage, not a fixed number of volts. A 3% drop on a 24 V system is 0.72 V, while on a 12 V system it’s only 0.36 V. Always use the percentage, not a fixed voltage.

Finally, don’t ignore the effect of ambient temperature. The resistance of copper increases with temperature, so if your cable runs in a hot environment (engine bay, rooftop), you may need to derate the current or increase the wire size. A common rule of thumb is to reduce ampacity by 10% for every 10°C above 30°C ambient.

Comparison: Copper vs. Aluminum

Copper is the default choice for most DC wiring because it has higher conductivity (56 vs. 35), meaning a smaller wire can carry the same current with less drop. Copper is also more flexible and easier to solder or crimp. The downsides are cost and weight.

Aluminum is about 60% lighter and cheaper, but you need a larger cross-section to achieve the same voltage drop. For example, if copper needs 4.96 mm², aluminum would need 4.96 × (56/35) ≈ 7.94 mm². Aluminum also requires special anti-oxidant paste and proper torque on connections to prevent corrosion and loosening.

For most small-scale DC projects (solar panels, boats, RVs, automotive), copper is recommended. Aluminum is more common in large utility-scale installations where weight and cost savings outweigh the drawbacks.

Safety and Installation Tips

Always fuse the cable at the source, rated at or below the cable’s ampacity. The fuse protects the wire, not the load. If a short occurs, the fuse should blow before the wire overheats.

Use the correct termination: crimp connectors that match the wire gauge, and use a proper crimping tool. Loose connections create resistance, which causes heat and voltage drop. For aluminum, use connectors rated for aluminum and apply anti-oxidant compound.

Keep cables as short as possible. Every meter of wire adds resistance and voltage drop. If you have a choice between running a long 12 V cable or moving the battery closer, moving the battery is always better.

Finally, consider the insulation rating. The calculator gives the conductor size, but the insulation must be rated for the voltage and environment (e.g., marine-grade for boats, UV-resistant for outdoor solar).

Frequently Asked Questions

What is the difference between AWG and mm²?

AWG (American Wire Gauge) is a logarithmic scale where a larger gauge number means a thinner wire. mm² is the actual cross-sectional area. The calculator gives both so you can use whichever standard your local suppliers stock. For example, 10 AWG is 5.26 mm², 12 AWG is 3.31 mm².

Can I use this calculator for AC circuits?

No. AC circuits have additional factors like reactance, power factor, and skin effect, especially at higher frequencies. This calculator is only for DC. For AC, you need a different formula that considers impedance, not just resistance.

What if the calculated size is between two standard gauges?

Always choose the larger (thicker) gauge. For example, if the calculator says 4.96 mm², you need at least 10 AWG (5.26 mm²), not 12 AWG (3.31 mm²). Rounding down can cause excessive voltage drop and overheating.

Does the length of the cable include both positive and negative wires?

No. The calculator asks for the one-way length (from source to load). The formula multiplies by 2 to account for the return path. If you enter the total loop length, you’ll get a wire twice as thick as needed.

Why is voltage drop important for solar panels?

Solar panels often produce low voltage (12–48 V) and are located far from the charge controller or battery. A small voltage drop can significantly reduce the power delivered. For example, a 3% drop on a 12 V panel means you lose 0.36 V, which is about 3% of your potential energy. Sizing the wire correctly minimizes this loss.

Can I use a thinner wire if the load is intermittent?

It depends. If the load is short and infrequent, a thinner wire might work without overheating, but the voltage drop during operation could still cause problems. For example, a winch motor that draws 100 A for 10 seconds might be okay with a thinner wire, but the voltage drop could reduce its pulling power. Always check the voltage drop for the worst-case current, not the average.

Related

Formula used
in v | System voltage | V | 12 | 0
in i | Load current | A | 10 | 0
in l | One-way cable length | m | 5 | 0
in pct | Max voltage drop | % | 3 | 0
in mat | Conductor material | copper=56, aluminum=35 | copper
out area | Required wire size | mm² | (2 * l * i) / (mat * (v * pct / 100)) | 2
out awg | Nearest AWG | - | round(1 - (log(area / 0.0005067) / log(92)) * 2, 0) | 0
out drop | Actual voltage drop | V | (2 * l * i) / (mat * area) | 2
out vload | Voltage at load | V | v - drop | 2

Each line is one input (in, sel, list) or one result (out: label, unit, formula, decimals). How the calculators work

Method: the standard formula for this calculation, rounded as each result states. See how the calculators work or report an error.