ThisCalculator

Everyday

Area Moment of Inertia Circle Calculator

Updated · Standard formula, shown below

The calculator for this page is switched off while it is checked. The formula is below, and the worked example in the article shows how to use it by hand.

This calculator finds the area moment of inertia (also called the second moment of area) of a solid circular cross-section about its centroidal axis. You enter the circle’s diameter or radius, and you get the moment of inertia in your chosen units (mm⁴, cm⁴, in⁴, etc.). The formula used is I = πr⁴/4 = πd⁴/64, which is the standard textbook expression for a solid circle.

Formula

The area moment of inertia of a solid circle about an axis through its centroid (the center) is given by:

I = π r⁴ / 4

or equivalently, using the diameter d:

I = π d⁴ / 64

Where:

  • I = area moment of inertia (units of length⁴, e.g., mm⁴, cm⁴, in⁴)
  • r = radius of the circle (same length unit as d)
  • d = diameter of the circle (2r)
  • π ≈ 3.14159

The formula assumes a solid (fully filled) circular cross-section. For a hollow circle (a ring), you subtract the inner circle’s moment from the outer circle’s moment.

Worked Example

Let’s use the default values from the calculator: a solid circle with a diameter of 100 mm.

  1. First, find the radius: r = d/2 = 100 mm / 2 = 50 mm.
  2. Apply the formula I = π r⁴ / 4 = π × (50 mm)⁴ / 4.
  3. Calculate (50)⁴ = 6,250,000 mm⁴.
  4. Multiply by π: 6,250,000 × 3.14159 = 19,634,954.08 mm⁴.
  5. Divide by 4: I = 4,908,738.5 mm⁴.

The calculator rounds to one decimal place, giving 4,908,738.5 mm⁴. This is the same result you get using the diameter version: π × (100)⁴ / 64 = 4,908,738.5 mm⁴.

Why the Area Moment of Inertia Matters

The area moment of inertia is not just a geometric curiosity – it directly quantifies how a cross-section resists bending and deflection. A beam with a larger I value is stiffer and deflects less under the same load. For example, when designing a circular shaft or a cylindrical column, engineers use I to calculate bending stress (σ = My/I) and deflection. Doubling the diameter of a circle increases its moment of inertia by a factor of 16 (since d⁴), which is why hollow tubes are so efficient: they place material far from the center, boosting I without much added weight.

How to Read the Result

The unit of I is always length to the fourth power. If you enter the diameter in millimeters, your result is in mm⁴. If you enter inches, you get in⁴. To convert between units, you must scale by the fourth power of the length conversion factor. For instance:

  • 1 cm = 10 mm, so 1 cm⁴ = 10⁴ mm⁴ = 10,000 mm⁴.
  • 1 in = 25.4 mm, so 1 in⁴ = (25.4)⁴ mm⁴ ≈ 416,231.4 mm⁴.

Many engineering tables list I for standard sections, but for a circle you can always compute it directly with this formula.

Common Mistakes and Misconceptions

A frequent error is using the radius in the diameter-based formula or vice versa. Always check which version you are applying. Another common mix-up is confusing the area moment of inertia (I) with the mass moment of inertia (J) used in rotational dynamics – they are different quantities with different units (length⁴ vs. mass·length²). Also, the polar moment of inertia (J) for a circle is exactly twice the area moment: J = πd⁴/32. Some people mistakenly use I when they need J for torsion problems.

Another subtle point: the formula I = πr⁴/4 is for an axis through the centroid. If you need the moment about an axis tangent to the circle (at the edge), you must use the parallel axis theorem: Itangent = Icentroid + A·r², where A is the area. For a circle that gives Itangent = (5/4)πr⁴.

When to Use This Calculator

Use this tool when you are:

  • Calculating bending stress in a circular beam or shaft.
  • Computing deflection of a cylindrical rod under load.
  • Designing circular columns or struts for buckling checks.
  • Working on any structural or mechanical problem that involves a solid circular cross-section.

If your cross-section is a hollow circle (a pipe or tube), you can still use this calculator twice: once for the outer diameter and once for the inner diameter, then subtract the inner I from the outer I. For example, a pipe with outer diameter 100 mm and inner diameter 80 mm has I = (π/64)(100⁴ – 80⁴) = (π/64)(10⁸ – 4.096×10⁷) ≈ 2,900,000 mm⁴.

Limitations of the Formula

The formula is exact for a perfect mathematical circle. In practice, real manufactured parts may have slight ovality (out-of-roundness), which changes the actual moment of inertia. For precision work, you may need to measure the actual dimensions at several points and average them. Also, the formula assumes a homogeneous, solid cross-section – it does not account for holes, ribs, or other internal features. For composite sections, you must break them into simple shapes and use the parallel axis theorem to combine their individual moments.

Frequently Asked Questions

What is the difference between area moment of inertia and polar moment of inertia?

The area moment of inertia (I) is about an axis lying in the plane of the cross-section (e.g., the x-axis or y-axis). The polar moment of inertia (J) is about an axis perpendicular to the cross-section (the z-axis, out of the page). For a circle, J = 2I because of symmetry. J is used in torsion calculations, while I is used in bending.

Does the moment of inertia change if I rotate the circle?

No. For a circle, the moment of inertia is the same about any diameter because the shape is perfectly symmetric. This is why circles are often preferred for shafts that experience bending in multiple directions – they have equal stiffness in all directions.

How do I find the moment of inertia of a semicircle?

A semicircle has a different centroid location, so you cannot simply halve the full circle’s I. The moment of inertia of a semicircle about its flat edge (the diameter) is I = πr⁴/8, and about the centroidal axis parallel to the edge it is I = (π/8 – 8/(9π))r⁴ ≈ 0.1098r⁴.

Can I use this for a hollow circle?

Yes, but not directly. Calculate I for the outer diameter and subtract I for the inner diameter. The formula becomes I = π(D⁴ – d⁴)/64, where D is the outer diameter and d is the inner diameter.

What are the units of the result?

The result is always length to the fourth power. If you enter millimeters, you get mm⁴; if you enter inches, you get in⁴. To convert, remember to raise the conversion factor to the fourth power (e.g., 1 in⁴ = 416,231.4 mm⁴).

Related

Formula used
in d | Diameter | mm | 100 | 0
out I | Area moment of inertia | mm⁴ | (pi * d^4) / 64 | 1
out r | Radius | mm | d / 2 | 1
out A | Area | mm² | pi * (d/2)^2 | 1

Each line is one input (in, sel, list) or one result (out: label, unit, formula, decimals). How the calculators work

Method: the standard formula for this calculation, rounded as each result states. See how the calculators work or report an error.